[" 83.If particle is thrown vertically upwards,then its "],[" velocity so that it covers sume distance in Sth and "],[" 6th seconds would be "]

If a particle is thrown vertically upwards , then its velocity so that it covers same distance in 5th and 6th seconds would be .

A ball is thrown vertically upwards with a certain velocity. Then

A particle is thrown vertically upward with speed 45 m//s . Find the distance covered by the particle in the 5^(th) second of its journey.

From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 m//s . The ratio of the distances, covered by it in the 3rd and 2nd seconds of the motion is ("Take" g = 10 m//s^2) .

From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 m//s . The ratio of the distances, covered by it in the 3rd and 2nd seconds of the motion is ("Take" g = 10 m//s^2) .

A particle is thrown up vertically with a velocity of 50 m/s. How high would the particle rise?