Evaluate: `int1/(sin^4xcos^2x)dx`

Explanation

`int frac{1}{sin ^{4} x cos ^{2} x} d x`
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=int frac{frac{1}{cos ^{6} x}}{frac{sin 4 cos ^{2} x}{cos ^{6} x}} d x`
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=int frac{sec ^{6} x}{frac{sin ^{4} x}{operatorname{coc}^{4} x}} d x`
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=int frac{sec ^{6} x}{tan ^{4} x} d x`
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=int frac{sec ^{4} x sec ^{2} x}{tan ^{4} x} d x`
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=int frac{(sec ^{2} x)^{2} sec ^{2} x}{tan ^{4} x} d x`
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