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intsinm xcosn xdx ,m!=n...

`intsinm xcosn xdx ,m!=n`

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`2 sin A cos B=sin (A+B)+sin (A-B)`
therefore `sin {mx} cos {nx}=frac{sin (m+n) x+sin (m-n) x}{2}`
therefore The above equation becomes
` Rightarrow int frac{1}{2}(sin (m+n) x+sin (m-n) x) d x`
We know `int sin a x d x=frac{-1}{a} cos a x+c`
` ...
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