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intcosm xcosn xdx ,m!=n...

`intcosm xcosn xdx ,m!=n`

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`2 cos A cos B=cos (A-B)+cos (A+B)`
therefore `cos {mx} cos n {X}=frac{cos (m-n) x+cos (m+n) x}{2}`
therefore, The above equatlon becomes
` Rightarrow int frac{1}{2}(cos (m-n) x+cos (m+n) x) {dx}`
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