Evaluate the following integrals : `intcos^(-1)(sinx)dx`

Explanation

`cos^(-1)(sinxx)=cos^(-1)[cos(pi/20x)]`

`=pi/2-x`

`intcos^(-1)(sinx)dx=int(pi/2-x)dx`

`=intpi/2dx-intxdx`

`=pi/2 2x-x^2/2+c`.