" Q."3quad (sin3 theta-sin thetasin^(2)(2 theta))/(sin theta+sin2 thetacos theta)=cos x rArr x=

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(sin3 theta-sin theta sin^(2)(2 theta))/(sin theta+sin2 theta cos theta)=cos x then x=

(sin 3 thea - sin theta sin ^(2) (2 theta ))/( sin theta + sin 2 theta cos theta ) = cos x implies x =

8sin theta cos theta cos2 theta cos4 theta=sin x rArr x=

sin^(3)theta + sin theta - sin theta cos^(2)theta =

8sin theta cos theta*cos2 theta cos4 theta=sin x rArr x=

(sin3 theta+cos3 theta)/(cos theta-sin theta)=1+2xx sin2 theta

sin theta+sin2 theta+sin3 theta=1+cos theta+cos2 theta

(sin5 theta-2sin3 theta + sin theta) / (cos5 theta-cos theta) = tan theta

(sin theta+cos theta)(1-sin theta cos theta)=sin^3 theta+cos^3 theta

3. sin^(3)theta+cos^(3)theta=(sin theta+cos theta)(1-sin theta cos theta)