(3x)/(2)-(5y)/(3)=-2,(x)/(3)+(y)/(2)=(13)/(6)

Solve the following using method of by substitution (3x)/(2)-(5y)/(3)+2=0 (x)/(3)+(y)/(2)=2.(1)/(6)

Find the value of x and y (1)/(2x)+(1)/(3y)=2 (1)/(3x)+(1)/(2y)=(13)/(6)

Solve for x and y:(2x+1)/(7)+(5y-3)/(3)=12(3x+2)/(2)-(4y+3)/(9)=13

(3x)/2-(5y)/3=-2" and "x/3+y/2=13/6

Multiply: (3x^(2)+y^(2))by(2x^(2)+3y^(2))((3)/(5)x+(1)/(2)y)by((5)/(6)x+4y)

Solve by cross-multiplication method. (i) 8x-3y=12,5x=2y +7 (ii) 6x+ 7y -11 =0, 5x+ 2y =13 (iii) (2)/(x)+(3)/(y) =5, (3)/(x) -(1)/(y) +9=0