Home
Class 12
MATHS
The slope of the tangent to the curve x=...

The slope of the tangent to the curve `x=t^2+3t-8,``y=2t^2-2t-5`at the point `(2, 1)`is(A) `(22)/7` (B) `6/7` (C) `7/6` (D) `(-6)/7`

Text Solution

AI Generated Solution

To find the slope of the tangent to the curve defined by the parametric equations \( x = t^2 + 3t - 8 \) and \( y = 2t^2 - 2t - 5 \) at the point \( (2, 1) \), we will follow these steps: ### Step 1: Find \( \frac{dy}{dt} \) and \( \frac{dx}{dt} \) 1. Differentiate \( y \) with respect to \( t \): \[ y = 2t^2 - 2t - 5 \implies \frac{dy}{dt} = 4t - 2 \] ...
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the slope of the tangent to the curve x=t^2+3t-8 , y=2t^2-2t-5 at t=2 .

The slope of the tangent to the curve x=t^2+3t-8,\ \ y=2t^2-2t-5 at the point (2,\ -1) is 22//7 (b) 6//7 (c) 7//6 (d) -6//7

For the curve x=t^(2) +3t -8 ,y=2t^(2)-2t -5 at point (2,-1)

The slope of the tangent to the curve x=t^2+3t-8,\ \ y=2t^2-2t-5 at point (2,\ -1) is 22//7 (b) 6//7 (c) -6 (d) 7//6

The slope of the tangent to the curves x=3t^2+1,y=t^3-1 at t=1 is

The slope of the tangent to the curve x =1/t, y =t - t/t , at t=2 is ………….

Slope of the tangent to the curve x=at^(2), y=2t at t=2 is ……………….. .

The slope of the tangent to the curve x=3t^2+1 , y=t^3-1 at x=1 is 1//2 (b) 0 (c) -2 (d) oo