Luis has `$25` to spend on school supplies. Pencils (p) cost `$1.25` per package, ntebooks (n) are priced at `$2.50` each, nad markers (m) sell for `$4` per pack. He must buy exactly one calendar/planner for `$5.75.` Which of the following describes how many markers Lusi can buy ?

Options

A. ` m le ( 19.25 + 2.5 m + 5.75)/(25)`
B. `m le (19.25-1.25p -2.5n )/(4)`
C. `m le ( 25-1 .25 p -2.5n )/(4)-5.75`
D. `m le 19.25 -1.25 -2.5n`

Explanation

To determine how many markers Luis can buy, we need to set up an inequality based on the total amount of money he has and the costs of the items he needs to purchase.

### Step-by-Step Solution:

1. **Identify the total amount Luis has**:
Luis has a total of $25 to spend on school supplies.

2. **Identify the cost of each item**:
- Pencils (p) cost $1.25 per package.
- Notebooks (n) cost $2.50 each.
- Markers (m) cost $4 per pack.
- Luis must buy one calendar/planner for $5.75.

3. **Set up the inequality**:
The total amount spent on all items must be less than or equal to $25. The equation can be set up as follows:
\[ 1.25p + 2.50n + 4m + 5.75 \leq 25 \]

4. **Isolate the term for markers**:
To find out how many markers (m) Luis can buy, we need to isolate the term involving m. First, subtract the cost of the calendar from both sides:
\[ 1.25p + 2.50n + 4m \leq 25 - 5.75 \]
Simplifying the right side:
\[ 25 - 5.75 = 19.25 \]
So we have:
\[ 1.25p + 2.50n + 4m \leq 19.25 \]

5. **Rearranging the inequality**:
Now, isolate the term for markers (m):
\[ 4m \leq 19.25 - 1.25p - 2.50n \]

6. **Divide by 4**:
To solve for m, divide the entire inequality by 4:
\[ m \leq \frac{19.25 - 1.25p - 2.50n}{4} \]

### Final Inequality:
Thus, the inequality that describes how many markers Luis can buy is:
\[ m \leq \frac{19.25 - 1.25p - 2.50n}{4} \]