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(7 +i)/(8-i) If the expression above i...

`(7 +i)/(8-i)`
If the expression above is expressed in the form `a +bi,` where `I = sqrt(-1,` what is the value of b ?

A

`-1`

B

`3/13`

C

`11/13`

D

`15/64`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \((7 + i)/(8 - i)\) and express it in the form \(a + bi\), we will follow these steps: ### Step 1: Rationalize the Denominator To eliminate the imaginary part in the denominator, we multiply both the numerator and the denominator by the conjugate of the denominator, which is \(8 + i\). \[ \frac{7 + i}{8 - i} \cdot \frac{8 + i}{8 + i} \] ### Step 2: Multiply the Numerators Now, we will multiply the numerators: \[ (7 + i)(8 + i) = 7 \cdot 8 + 7 \cdot i + i \cdot 8 + i \cdot i \] Calculating this gives: \[ 56 + 7i + 8i + i^2 \] Since \(i^2 = -1\), we can substitute that in: \[ 56 + 15i - 1 = 55 + 15i \] ### Step 3: Multiply the Denominators Next, we multiply the denominators: \[ (8 - i)(8 + i) = 8^2 - i^2 = 64 - (-1) = 64 + 1 = 65 \] ### Step 4: Combine the Results Now we can combine the results from the numerator and denominator: \[ \frac{55 + 15i}{65} \] ### Step 5: Separate the Real and Imaginary Parts We can separate this into real and imaginary parts: \[ \frac{55}{65} + \frac{15}{65}i \] ### Step 6: Simplify the Fractions Now, simplify the fractions: \[ \frac{55}{65} = \frac{11}{13} \quad \text{and} \quad \frac{15}{65} = \frac{3}{13} \] Thus, we have: \[ \frac{11}{13} + \frac{3}{13}i \] ### Step 7: Identify \(b\) In the form \(a + bi\), we can see that \(b = \frac{3}{13}\). ### Final Answer The value of \(b\) is \(\frac{3}{13}\). ---
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