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Rewriite problem by either distributings...

Rewriite problem by either distributings or factoring and then solve. Question 3, 4, and 5 have no numbers in them, therefore, they can't be solved with a calculator.
Q. `51(48)+51(50)+51(52)`=_____

Text Solution

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The correct Answer is:
To solve the expression \( 51(48) + 51(50) + 51(52) \) by factoring, we can follow these steps: ### Step 1: Identify the common factor Notice that \( 51 \) is a common factor in all three terms of the expression. ### Step 2: Factor out the common factor We can factor \( 51 \) out from the expression: \[ 51(48) + 51(50) + 51(52) = 51(48 + 50 + 52) \] ### Step 3: Simplify the expression inside the parentheses Now, we need to simplify the expression inside the parentheses: \[ 48 + 50 + 52 \] Calculating this gives: \[ 48 + 50 = 98 \] \[ 98 + 52 = 150 \] So, we have: \[ 48 + 50 + 52 = 150 \] ### Step 4: Substitute back into the factored expression Now we can substitute back into the factored expression: \[ 51(150) \] ### Step 5: Multiply to find the final result Now, we multiply: \[ 51 \times 150 \] Calculating this gives: \[ 51 \times 150 = 7650 \] ### Final Answer Thus, the final result of the expression \( 51(48) + 51(50) + 51(52) \) is: \[ \boxed{7650} \]
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Knowledge Check

  • A national math examination has 4 statics problems. The distribution of the number of students who ansered the question correctly is shown in the chart. If 400 students took the exam and each question was worth 25 points, then what is the average score of the students taking the exam? {:("Question Number","Number of students who solved the question"),(1,200),(2,304),(3,350),(4,250):}

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