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For the equation (a^(x))/(a^(y))=a^(10) ...

For the equation `(a^(x))/(a^(y))=a^(10) and (a^(y))^(3)=a^(x)`, if `agt1`, what is the value of x?

A

`5`

B

`10`

C

`15`

D

`20`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equations \(\frac{a^x}{a^y} = a^{10}\) and \((a^y)^3 = a^x\), we will follow these steps: ### Step 1: Simplify the first equation The first equation can be simplified using the properties of exponents: \[ \frac{a^x}{a^y} = a^{x-y} \] Thus, we can rewrite the equation as: \[ a^{x-y} = a^{10} \] Since the bases are the same, we can equate the exponents: \[ x - y = 10 \quad \text{(Equation 1)} \] ### Step 2: Simplify the second equation The second equation can also be simplified: \[ (a^y)^3 = a^{3y} \] So we can rewrite the equation as: \[ a^{3y} = a^x \] Again, equating the exponents gives us: \[ 3y = x \quad \text{(Equation 2)} \] ### Step 3: Substitute Equation 2 into Equation 1 Now we will substitute \(x\) from Equation 2 into Equation 1: \[ 3y - y = 10 \] This simplifies to: \[ 2y = 10 \] ### Step 4: Solve for \(y\) Now, we can solve for \(y\): \[ y = \frac{10}{2} = 5 \] ### Step 5: Substitute \(y\) back to find \(x\) Now that we have \(y\), we can substitute it back into Equation 2 to find \(x\): \[ x = 3y = 3 \times 5 = 15 \] ### Final Answer Thus, the value of \(x\) is: \[ \boxed{15} \] ---
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Knowledge Check

  • if x-y=y+3=7, what is the value of x?

    A
    `-4`
    B
    8
    C
    10
    D
    11
  • If (x-3y)/(x)=7 , what is the value of (x)/(y) ?

    A
    `-(8)/(3)`
    B
    `-2`
    C
    `-(1)/(2)`
    D
    `(3)/(8)`
  • If x-y=3 and x+y=5 , what is the value of y?

    A
    `-4`
    B
    `-2`
    C
    `-1`
    D
    `1`
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