A certain store sells televisions ranging in price for $500 to $5,000 in increment of $500. The graph above shows the total number of television sold at each price durind the last 12 months. Approximately how much more revenue did the store collect from the television it sold price at $3,500 then it did from the television it sold price at $1,000?

Options

A. $175lt000
B. 250000
C. 275000
D. 350000

Answer

To solve the problem, we need to calculate the revenue generated from televisions sold at two different price points: $3,500 and $1,000. We will then find the difference between these two revenues.

### Step-by-Step Solution:

1. **Identify the number of televisions sold at each price point.**
- From the graph, we find that:
- At $3,500, the number of televisions sold is **150**.
- At $1,000, the number of televisions sold is **250**.

2. **Calculate the revenue from televisions sold at $3,500.**
- Revenue is calculated as:
\[ \text{Revenue} = \text{Price} \times \text{Number of Televisions Sold} \]
- For $3,500:
\[ \text{Revenue}_{3500} = 3500 \times 150 = 525000 \]

3. **Calculate the revenue from televisions sold at $1,000.**
- For $1,000:
\[ \text{Revenue}_{1000} = 1000 \times 250 = 250000 \]

4. **Determine how much more revenue was collected from the $3,500 televisions compared to the $1,000 televisions.**
- We find the difference between the two revenues:
\[ \text{Difference} = \text{Revenue}_{3500} - \text{Revenue}_{1000} \]
- Substituting the values:
\[ \text{Difference} = 525000 - 250000 = 275000 \]

5. **Conclusion:**
- The store collected **$275,000** more revenue from televisions sold at $3,500 than from those sold at $1,000.

### Final Answer:
The store collected $275,000 more revenue from the televisions sold at $3,500 than from those sold at $1,000.

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