At this bake sale, Mr. Heftwhistle sold 30% of his pies to one friend. Mr.. Heftwhistle then sold 60% of the remaining pies to another friend. What percent of his original number of pies did Mr. Hefrwhistle have left?
A
`10%`
B
`18%`
C
`28%`
D
`36%`
Text Solution
AI Generated Solution
The correct Answer is:
To solve the problem step by step, let's denote the total number of pies Mr. Heftwhistle originally had as \( X \).
### Step 1: Calculate the number of pies sold to the first friend.
Mr. Heftwhistle sold 30% of his pies to the first friend.
\[
\text{Pies sold to the first friend} = 30\% \text{ of } X = \frac{30}{100} \times X = 0.3X
\]
### Step 2: Calculate the number of pies remaining after the first sale.
After selling 30% of his pies, the number of pies left is:
\[
\text{Remaining pies} = X - 0.3X = 0.7X
\]
### Step 3: Calculate the number of pies sold to the second friend.
Mr. Heftwhistle then sold 60% of the remaining pies to the second friend. The remaining pies are \( 0.7X \).
\[
\text{Pies sold to the second friend} = 60\% \text{ of } 0.7X = \frac{60}{100} \times 0.7X = 0.6 \times 0.7X = 0.42X
\]
### Step 4: Calculate the number of pies remaining after the second sale.
After selling 60% of the remaining pies, the number of pies left is:
\[
\text{Remaining pies} = 0.7X - 0.42X = 0.28X
\]
### Step 5: Calculate the percentage of the original number of pies left.
Now, we need to find out what percent of the original number of pies \( X \) is left. We can express this as:
\[
\text{Percentage left} = \left( \frac{0.28X}{X} \right) \times 100\%
\]
Since \( X \) cancels out, we have:
\[
\text{Percentage left} = 0.28 \times 100\% = 28\%
\]
### Final Answer:
Mr. Heftwhistle has **28%** of his original number of pies left.
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