A store sells shirts fro $7.50 each and hats for $5.00 each. The store earns $1,822.50 in one day from selling a total of 307 shirts and hats. How many shirts were sold on that day?
A store sells shirts fro $7.50 each and hats for $5.00 each. The store earns $1,822.50 in one day from selling a total of 307 shirts and hats. How many shirts were sold on that day?
A
`37`
B
`89`
C
`115`
D
`202`
Text Solution
AI Generated Solution
The correct Answer is:
To solve the problem, we will set up a system of equations based on the information given.
### Step 1: Define the Variables
Let:
- \( X \) = number of shirts sold
- \( Y \) = number of hats sold
### Step 2: Set Up the Equations
From the problem, we know:
1. The total number of shirts and hats sold is 307:
\[
X + Y = 307 \quad \text{(Equation 1)}
\]
2. The total earnings from selling shirts and hats is $1,822.50:
\[
7.50X + 5.00Y = 1822.50 \quad \text{(Equation 2)}
\]
### Step 3: Solve for One Variable
We can solve Equation 1 for \( Y \):
\[
Y = 307 - X
\]
### Step 4: Substitute into the Second Equation
Now, substitute \( Y \) in Equation 2:
\[
7.50X + 5.00(307 - X) = 1822.50
\]
### Step 5: Simplify the Equation
Distributing the 5.00:
\[
7.50X + 1535 - 5.00X = 1822.50
\]
Combine like terms:
\[
(7.50 - 5.00)X + 1535 = 1822.50
\]
\[
2.50X + 1535 = 1822.50
\]
### Step 6: Isolate \( X \)
Subtract 1535 from both sides:
\[
2.50X = 1822.50 - 1535
\]
\[
2.50X = 287.50
\]
### Step 7: Solve for \( X \)
Divide both sides by 2.50:
\[
X = \frac{287.50}{2.50}
\]
\[
X = 115
\]
### Conclusion
The number of shirts sold on that day is \( \boxed{115} \).
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