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The surface area of a rectangular solid ...

The surface area of a rectangular solid measuring `5times6times8` is how much greater than the surface area of a rectangular solid measuring `3times6times8`?

A

`12`

B

`24`

C

`48`

D

`56`

Text Solution

AI Generated Solution

The correct Answer is:
To find how much greater the surface area of a rectangular solid measuring \(5 \times 6 \times 8\) is than that of a rectangular solid measuring \(3 \times 6 \times 8\), we will follow these steps: ### Step 1: Calculate the surface area of the first rectangular solid The formula for the surface area \(SA\) of a rectangular solid is given by: \[ SA = 2 \times (lw + lh + wh) \] where \(l\) is the length, \(w\) is the width, and \(h\) is the height. For the first solid with dimensions \(5\), \(6\), and \(8\): - Length \(l = 5\) - Width \(w = 6\) - Height \(h = 8\) Substituting the values into the formula: \[ SA_1 = 2 \times (5 \times 6 + 5 \times 8 + 6 \times 8) \] ### Step 2: Calculate each term inside the parentheses Calculating each term: - \(5 \times 6 = 30\) - \(5 \times 8 = 40\) - \(6 \times 8 = 48\) Now, add these values: \[ 30 + 40 + 48 = 118 \] ### Step 3: Multiply by 2 to find the total surface area Now, multiply by 2 to find the surface area: \[ SA_1 = 2 \times 118 = 236 \text{ square units} \] ### Step 4: Calculate the surface area of the second rectangular solid For the second solid with dimensions \(3\), \(6\), and \(8\): - Length \(l = 3\) - Width \(w = 6\) - Height \(h = 8\) Using the same formula: \[ SA_2 = 2 \times (3 \times 6 + 3 \times 8 + 6 \times 8) \] ### Step 5: Calculate each term inside the parentheses for the second solid Calculating each term: - \(3 \times 6 = 18\) - \(3 \times 8 = 24\) - \(6 \times 8 = 48\) Now, add these values: \[ 18 + 24 + 48 = 90 \] ### Step 6: Multiply by 2 to find the total surface area of the second solid Now, multiply by 2 to find the surface area: \[ SA_2 = 2 \times 90 = 180 \text{ square units} \] ### Step 7: Find the difference in surface areas Now, we need to find how much greater the surface area of the first solid is than the second solid: \[ \text{Difference} = SA_1 - SA_2 = 236 - 180 \] ### Step 8: Calculate the difference Calculating the difference: \[ \text{Difference} = 56 \text{ square units} \] ### Final Answer The surface area of the rectangular solid measuring \(5 \times 6 \times 8\) is \(56\) square units greater than that of the rectangular solid measuring \(3 \times 6 \times 8\). ---
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