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The equation (x+4)^(2)+(y-7)^(2)=25 repr...

The equation `(x+4)^(2)+(y-7)^(2)=25` represents a circle in the xy-plane . Points A and B on the circle are the endpoints of diameter, and point A has coordinates (-4, 2). What are the coordinates of point B?

A

`(-9, 7)`

B

`(-4, 12)`

C

`(-4, 7)`

D

`(1, 7)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the coordinates of point B, we will follow these steps: ### Step 1: Identify the center and radius of the circle The equation of the circle is given as: \[ (x + 4)^2 + (y - 7)^2 = 25 \] This can be compared to the standard form of a circle's equation: \[ (x - h)^2 + (y - k)^2 = r^2 \] where \((h, k)\) is the center and \(r\) is the radius. From the given equation, we can see: - \(h = -4\) - \(k = 7\) - \(r^2 = 25\) which gives \(r = 5\) ### Step 2: Find the coordinates of point A We are given that point A has coordinates: \[ A(-4, 2) \] ### Step 3: Determine the coordinates of point B Since A and B are endpoints of the diameter of the circle, the center of the circle is the midpoint of segment AB. The coordinates of the center (h, k) can be calculated as: \[ \left(\frac{x_A + x_B}{2}, \frac{y_A + y_B}{2}\right) = (h, k) \] Substituting the known values: \[ \left(\frac{-4 + x_B}{2}, \frac{2 + y_B}{2}\right) = (-4, 7) \] ### Step 4: Set up the equations From the x-coordinates: \[ \frac{-4 + x_B}{2} = -4 \] Multiplying both sides by 2: \[ -4 + x_B = -8 \] Solving for \(x_B\): \[ x_B = -8 + 4 = -4 \] From the y-coordinates: \[ \frac{2 + y_B}{2} = 7 \] Multiplying both sides by 2: \[ 2 + y_B = 14 \] Solving for \(y_B\): \[ y_B = 14 - 2 = 12 \] ### Step 5: Write the coordinates of point B Thus, the coordinates of point B are: \[ B(-4, 12) \] ### Summary The coordinates of point B are \((-4, 12)\). ---
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