Charles Lindbergh began his flight from New York to Paris on May 20, 1927. In the course of his flight across the Atlantic Ocean Lindbergh travelled approximately 5,800 kilometers in 2,010 minutes. What was the average speed of the airplane during his flight, to the nearest kilometers per hour?

Answer

To find the average speed of Charles Lindbergh's airplane during his flight from New York to Paris, we can follow these steps:

### Step 1: Identify the given values
- Distance traveled = 5,800 kilometers
- Time taken = 2,010 minutes

### Step 2: Convert time from minutes to hours
To convert minutes into hours, we use the conversion factor that 1 hour = 60 minutes. Thus, we divide the number of minutes by 60.

\[ \text{Time in hours} = \frac{2010 \text{ minutes}}{60} = 33.5 \text{ hours} \]

### Step 3: Calculate the average speed
The formula for average speed is given by:

\[ \text{Average Speed} = \frac{\text{Distance}}{\text{Time}} \]

Substituting the values we have:

\[ \text{Average Speed} = \frac{5800 \text{ km}}{33.5 \text{ hours}} \approx 173.134 \text{ km/h} \]

### Step 4: Round the average speed to the nearest kilometer per hour
Since we need to round the average speed to the nearest kilometer per hour, we round 173.134 to 173 km/h.

### Final Answer
The average speed of the airplane during his flight was approximately **173 km/h**.

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