The normal to the curve `x^2=4y`passing (1,2) is(A) `x + y = 3` (B) `x - y = 3` (C) `x + y = 1` (D) `x - y = 1`

Explanation

To find the normal to the curve \( x^2 = 4y \) that passes through the point \( (1, 2) \), we can follow these steps:

### Step 1: Identify the curve and the point
The curve given is \( x^2 = 4y \). We need to find a point \( (h, k) \) on this curve such that the normal at this point passes through \( (1, 2) \).

### Step 2: Differentiate the curve to find the slope of the tangent
To find the slope of the tangent line at any point on the curve, we differentiate \( x^2 = 4y \) with respect to \( x \):

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