In a right triangle ABC, right angled at A, on the leg AC as diameter, a semicircle is described. The chord joining A with the point of intersection D of the hypotenuse and the semicircle, then the length AC equals to

In a triangle ABC, right angled at A, on the leg AC as diameter, semicircle is described. If a chord joins A with the point of intersection D of the hypotenuse and the semicircle, then the length of AC equals to

In a triangle ABC, right angled at A, on the leg AC as diameter,a semicircle is described.If a chord joi A with the point of intersection D of the hypotenuse and the semicircle,then the length of AC equals to

In a triangle ABC, right angled at A, on the leg AC as diameter,a semicircle is described. If a chord joins A with the point of intersection D of the hypotenuse and the semicircle,then the length of AC is equal to (AB.AD)/(sqrt(AB^(2)+AD^(2))) (b) (AB.AD)/(AB+AD)sqrt(AB.AD)(d)(AB.AD)/(sqrt(AB^(2)-AD^(2))) (b)

In a triangle A B C , right angled at A , on the leg A C as diameter, a semicircle is described. If a chord joins A with the point of intersection D of the hypotenuse and the semicircle, then the length of A C is equal to (A BdotA D)/(sqrt(A B^2+A D^2)) (b) (A BdotA D)/(A B+A D) sqrt(A BdotA D) (d) (A BdotA D)/(sqrt(A B^2-A D^2))

In a triangle A B C , right angled at A , on the leg A C as diameter, a semicircle is described. If a chord joins A with the point of intersection D of the hypotenuse and the semicircle, then the length of A C is equal to (a) (A B.A D)/(sqrt(A B^2+A D^2)) (b) (A B.A D)/(A B+A D) (c) sqrt(A B.A D) (d) (A B.A D)/(sqrt(A B^2-A D^2))

In a right triangle ABC right-angled at B, if P and Q are points on the side AB and AC respectively, then___

ABC is right triangle right angled at B.If BD is the length of the perpendicular drawn from B to AC then

In a right triangle ABC, a circle with AB as diameter is drawn to intersect the hypotenuse AC in P. Prove that the tangent at P, bisects the side BC.

In a right triangle ABC, a circle with a side. AB as diameter is drawn to intersect the hypotenuse AC in P. Prove that the tangent to the circle at P bisects the side BC.