((1-cos theta)(1+cos theta))/((1-sin theta)(1+sin theta))=tan^(2)theta

(sin theta)/(1-cos theta)=(1+cos theta)/(sin theta)

(1-sin theta)/(cos theta)-(cos theta)/(1+sin theta)=2tan theta

1-(sin^(2) theta)/(1+cos theta) + (1+cos theta)/(sin theta) - (sin theta)/(1-cos theta) - (1)/(sec theta)=

1-(sin^(2)theta)/(1+cos theta)+(1+cos theta)/(sin theta)-(sin theta)/(1-cos theta) equals

(1-cos theta)/(sin theta)=(sin theta)/(1+cos theta)

(1-cos theta)/(sin theta)=(sin theta)/(1+cos theta)

The value of sec theta((1+ sin theta)/(cos theta) + (cos theta)/(1+sin theta))- 2 tan^2 theta is

Prove that: :(1+sin theta-cos theta)/(1+sin theta+cos theta)=tan(theta)/(2)

Prove that (1- cos theta + sin theta)/( 1+cos theta +sin theta) = "tan"(theta)/(2) .

(cos^(2)theta(1-cos theta))/(sin^(2)theta(1-sin theta))=(1+sin theta)/(1+cos theta)