" (i) "[x+y-z=,3],[2x+3y+z=,10],[3x-y-7z=,1]

Solve the following system of equations by matrix method: x+y-z=3,2x+3y+z=10,3x-y-7z=1

Solve the following system of equations by matrix method: x+y-z=3 , 2x+3y+z=10 ,3x-y-7z=1

Using matrices, solve the following system of equations for x,y and z: {:(x+y-z=3),(2x+3y+z=10),(3x-y-7z=1):}

Solve the following system of equations by matrix method : x+y-2z=3 , 2x+3y+z=10 and 3x-y-7z=1

If we represent the linear equations x + y - z = 3, 2x + 3y + z = 10 and 3x - y - 7z = 1 in matrix form as AX = B, then A^(T) is:

If A = [(1,2,3),(1,3,-1),(-1,1,-7)] , find A^(-1) , hence solve the following system of linear equations: x + y - z = 3 , 2x + 3y +z 10 and 3x - y - 7z = 1

x+y-z=1 3x+y-2z=3 x-y-z=-1

Show that the following system of equations has no solution : x+2y+3z=1,2x+3y+5z=1,3x+4y+7z=1

Solve the system: x + y - 2z = 0, 2x - 3y + z = 0, 3x - 7y + 10z = 0, 6x - 9y + 10z = 0.