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[Clus(6)+(sqrt(3)-1)/(sqrt(3)+1),=a-b sq...

[Clus_(6)+(sqrt(3)-1)/(sqrt(3)+1),=a-b sqrt(3)*" then "],[(a),a=2,b=1quad (b)a=2,b=1quad (c)a=-2,b=1quad (a)]

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