Determine the points on the curve `x^2=4y` which are nearest to the point (0,5).

Explanation

`d=sqrt((x_1-o)^2+(y_1-5)^2)`

`d=sqrt(4y_1+(y_1-5)^2`

`d/(dy_1)=1/(2sqrt(4y_1+(y_1-5)^2))*(4+2(y_1-5))=0`

`4+(2(y_1-5)=0`

`y_1=3`

`x_1^2=4y_1`

`x_1=pm2sqrt3`

Points=`(2sqrt3,3),(-2sqrt3,3).`