(1)64

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log_(16)64-log_(64)16

The square root of 64 divided by the cube root of 64 is (a)64 (b) 2 (c) 1/2 (d) 64^(2/3)

Simplify: 64^(-1/3)[64^(1/3)-64^(2/3)]

(64)^((1)/(3))[(64)^((1)/(3))-(64)^((2)/(3))]=?

Find 36 - (-64) and (-64) - 36. Are they equal?

Say True or False: (-64) ÷ (-64) is 0

The square root of 64 divided by the cube root of 64 is 64 (b) 2(c)(1)/(2) (d) 64^((2)/(3))

cos{(2pi)/(2^(64)-1)}cos{(2^2pi)/(2^(64)-1)}......cos{(2^(64)pi)/(2^(64)-1)}=