When a mixture of 10 moles of `SO_(2)` and 16 moles of `O_(2)` were passed over a catalyst, 8 moles of `SO_(3)` were formed at equilibrium. The number of `SO_(2) and O_(2)` remaining unreacted were:

When a mixture consisting of 10 moles of SO_2 and 16 moles of O_2 were passed over a catalyst , 8 mole of SO_3 were formed at equilibrium.The number of moles of SO_2 and O_2 which did not enter into reation were :

When a mixture of 10 moles of SO_(2) and 15 moles of O_(2) was passed over catalyst, 8 moles of SO_(3) was formed. How many moles of SO_(2) and O_(2) did not enter into combination?

When a mixture of 10 moles of SO_(2) and 15 moles of O_(2) was passed over catalyst, 8 moles of SO_(3) was formed. How many moles of SO_(2) and O_(2) did not enter into combination?

When a mixture of 10 moles of SO_(2) and 15 moles of O_(2) was passed over catalyst, 8 moles of SO_(3) was formed. How many moles of SO_(2) and O_(2) did not enter into combination?

10 moles SO_(2) and 15 moles O_(2) were allowed to react over a suitable catalyst. 8 moles of SO_(3) were formed. The remaining moles of SO_(2) and O_(2) respectively are -

10 "mole of" kSO_(2) and 15 "mole of" O_(2) were passed over catalyst to produce 8 "mole of" SO_(3) . The ratio of SO_(2) and SO_(3) moles in mixture is:

Initially 0.4 mole of N_(2) and 0.9 mole of O_(2) were mixed then moles of N_(2),O_(2) and NO at equilibrium are (approximate):

5 moles of SO_(2) and 5 moles of O_(2) react in a closed vessel. At equilibrium 60% of the SO_(2) is consumed . The total number of gaseous moles (SO_(2),O_(2)andSO_(3)) in the vessel is :-