6x+3y=2:x-(y)/(2)=(1)/(2)

Find the value of x and y (1)/(2x)+(1)/(3y)=2 (1)/(3x)+(1)/(2y)=(13)/(6)

Solve for x and y (2)/(x)+(2)/(3y)=(1)/(6),(3)/(x)+(2)/(y)=0

Solve for x and y(3)/(x)+(2)/(y)=6 and (1)/(y)-(1)/(2x)=2

Find the greatest and least value of y= x^(3)-3x^(2) + 6x-2 on [-1,1] y is differentiable function of x and y'(x) = 3x^(2) -6x + 6= 3(x^(2) -2x+2) =3(x-1)^(2) gt 0 .

Find each of the following products: (i) (x - 4)(x - 4) (ii) (2x - 3y)(2x - 3y) (iii) ((3)/(4) x - (5)/(6) y) ((3)/(4)x - (5)/(6) y) (iv) (x - (3)/(x)) (x - (3)/(x)) (v) ((1)/(3) x^(2) - 9) ((1)/(3) x^(2) - 9) (vi) ((1)/(2) y^(2) - (1)/(3) y) ((1)/(2) y^(2) - (1)/(3) y)

If (2x + y + 2)/(5) = ( 3x - y + 1)/( 3 ) = ( 2 x + 2y + 1 )/(6) then

Simplify: (1)/(3)(6x^(2)+15y^(2))(6x^(2)-15y^(2))

Prove that the centres of the circles x^(2)+y^(2)=1,x^(2)+y^(2)+6x-2y-1=0 and x^(2)+y^(2)-12x+4y=1 are collinear