62+7x+(3)/(x)=35(3)/(5)

Solve by factorization: 7x+(3)/(x)=35(3)/(5)

If x= (3)/(4.8) + (3.5)/(4.8.12)+ (3.5.7)/(4.812.16) + …., then 2x^2+5x=

If x^(2)+9y^(2)+35z62=xyz((15)/(x)+(5)/(y)+(3)/(z)) then x,y,z in

Solve: (3x)/(7)-(4)/(35)=(2x)/(5)

Assertion (A) : (1)/(5)+(1)/(3.5^(3))+(1)/(5.5^(5))+(1)/(7.5^(7))+…(1)/(2)log((3)/(2)) Reason (R ) : If |x| lt 1 then log_(e )((1+x)/(1-x))=2(x+(x^(3))/(3)+(x^(5))/(5)+…)

Solve by factorization: 7x+3/x=35 3/5

If the sum to infinity of the series 1 + 4x + 7x^2 + 10x^3 +............. is 35/16 then x= (A) 1/5 (B) 2/5 (C) 3/7 (D)1/7

If the sum to infinity of the series 1 + 4x + 7x^2 + 10x^3 +............. is 35/16 then x= (A) 1/5 (B) 2/5 (C) 3/7 (D) 1/7

If the sum to infinity of the series 1 + 4x + 7x^2 + 10x^3 +............. is 35/16 then x= (A) 1/5 (B) 2/5 (C) 3/7 (D) 1/7

3((7x+1)/(5x-3))-4((5x-3)/(7x+1))=11;x!=(3)/(5),-(1)/(7)