[ax+by-a+b=0],[bx-ay-a-b=0]

By cross multiplication method,solve the pair of equation: ax+by+a=0, bx+ay+b=0

Solve the following system of equations b(x)/(a)-a(y)/(b)+a+b=0,bx-ay+2ab=0

ax+by=a-b;bx-ay=a+b

The equation of a line perpendicular to line ax+by+c=0 and passing through (a,b) is equal to ................ A) bx-ay=0 B) bx+ay-2ab=0 C) bx+ay=0 D) bx-ay+ 2ab=0

The straight line x-y-2=0 cuts the axis of x at A. It is rotated about A in such a manner that it is perpendicular to ax+by+c=0. Its equation is: (a) bx-ay-2b=0 (b) ax-by-2a=0 (c) bx+ay-2b=0 (d) ax+by+2a=0

If a!=b, then the system of equations ax+by+bz=0,bx+ay+bz=0,bx+by+az=0 will have a non-trivial solution if (1)a+b=0 (2) a+2b=0 (3) 2a+b=0(4)a+4b=0

The line parallel to the X-axis and passing through the point of intersection of the lin ax+2by+3b=0 and bx-2ay-3a=0 where (a,b)!=(0,0) is

The line parallel to the x axis and passing through the intersection of the lines ax+2by+3b=0 and bx -2ay-3a=0 where (a,b) ne (0,0) is

The lines parallel ot the x-axis and passing through the intersection of the lines ax+2by+3b=0 and bx-2ay-3a=0 [where (a,b)ne (0,0)] is-