Let `f(x) = (1-sinx)/(pi - 2x)^2 * ln(sinx)/ln(1 + pi^2 - 4pix + 4x^2)`, `x!= pi/2`. The value of `f(pi/2)` so that the function is continuous at `x=pi/2` is:

Let f(x)=(1-sin x)/((pi-2x)^(2))*(ln(sin x))/(ln(1+pi^(2)-4 pi x+4x^(2))),x!=(pi)/(2). The value of f((pi)/(2)) so that the function is continuous at x=(pi)/(2) is:

The function f(x)=(sin2x)^(tan^2 2x) is not defined at x=pi/4 . The value of f(pi/4) so that f is continuous at x=pi/4

The function f(x)=(sinx)^(tan^(2)x) is not defined at x=(pi)/(2) . The value of f((pi)/(2)) such that f is continuous at x=(pi)/(2) is

Consider the function f(x)=(1-sinx)/((pi-2x)^(2)) where xne(pi)/(2)andf((pi)/(2))=lambda What is the value of lambda . If the function is continuous at x=(pi)/(2) ?

Let f(x) = [sinx] , is f continuous at x = pi/2

The function f(x)=(sin 2x)^(tan^(2)2x) is not defined at x=(pi)/(4) . The value of f(pi//4) , so that f is continuous at x=pi//4 , is

Let f(x)=(cos x -sinx)/(cos 2x)+ sin^2x , x ne pi/4 . The value of f(pi//4) so that f is continuous on (0,pi//2) is (sqrt2=1.41)

Let f(x)=(sqrt2-(cosx+sinx))/(1-sin2x), x ne pi//4 . The value f(pi//4) so that f is continuous is (sqrt2=1.41)