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Show that f(x)=|x-3| is continuous at x=...

Show that `f(x)=|x-3|` is continuous at `x=3.`

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`f(x)= |x-3|`
For the continuity at `x=3`
`f(3)=0`
`text { LHL }=lim _{x -> 3} f(x) `
`text{LHL}=lim _{h -> 0} f({3}-h) `
`text{LHL}=lim _{h -> 0} |3-h-3|`
`text{LHL} = lim _{h -> 0} h=0`
Now,
...
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