Show that the function `f` defined as follows `f(x)={3x-2 , 0ltxle1 ; 2x^2-x , 1ltxle2 ; 5x-4 , xgt2,` is continous at x=2 but not differentiable.

Explanation

To show that the function \( f \) is continuous at \( x = 2 \) but not differentiable, we will follow these steps:

### Step 1: Define the function
The function \( f \) is defined as:
\[
f(x) =
\begin{cases}
3x - 2 & \text{for } 0 < x \leq 1 \\
...