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One kilogram sample of hard water contai...

One kilogram sample of hard water contains 4.44 mg of `CaCl_(2)` and 1.9 mg of NaCl. The total hardness in tems of ppm of `CaCO_(3)` is :

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One litre of a sample of hard water contain 4.44mg CaCl_(2) and 1.9mg "of" MgCl_(2) . What is the total hardness in terms of ppm of CaCO_(3)?

One litre of a sample of hard water contains 5.55 mg of CaCl_(1) and 4.75 mg of MgCl_(2) . The total harness of ppm of CaCO_(3) is

One litre of sample of hard water contains 0.8 mg of CaCl_(2) and "0.8 mg of MgCl"_(2) . Find the total hardness in terms of parts of CaCO_(3) , per 10^(6) parts of water by mass.

One litre of a sample of hard water contains 1 mg of CaCl_(2) and 1 mg of MgCl_(2) . Find the total hardness of water in terms of parts of CaCO_(3) per 10^(6) parts of water by mass.

One litre sample of water contains 0.9 mg CaCl_(2) and 0.9 mg of MgCl_(2) . Find the total hardness in terms of parts permillion of CaCO_(3) .

A water is said to be soft water if it produces sufficient foam with the soap and water that does not produce foam with soap is known as hard water. Hardness has been classified into two types (i)Temporary hardness (ii) Permanent hardness. Temporary hardness is due to presence of calcium and magnesium bicarbonate. It is simply removed by boiling as Ca(HCO_(3))_(2)overset(Delta)rarr CaCO_(3)darr+CO_(2)uarr+H_(2)O Mg(HCO_(3))_(2)overset(Delta)rarr MgCO_(3)darr+CO_(2)uarr+H_(2)O temporary hardness can also be removed by addition of slaked lime, Ca(OH)_(2) Ca(HCO_(3))_(2)+Ca(OH)_(2) to 2CaCO_(3)darr+2H_(2)O permanent hardsness is due to presencce of sulphates and chlorides of Ca,Mg,etc. It is removed by washing soda as CaCl_(2)+Na_(2)CO_(3) to CaCO_(3)darr+2NaCl CaSO(4)+Na_(2)CO_(3)to CaCO_(3)darr+Na_(2)SO_(4) Permanent hardness also removed by ion exchange resin process as 2RH+Ca^(2+)toR_(2)Ca+2H^(+) 2ROH+SO_(4)^(2-) to R_(2)SO_(4)+2OH^(-) The degree of hardness of water is measured in terms of PPm of CaCO_(3) 100 PPm means 100 g of CaCO_(3) is present in 10^(6) g of H_(2)O . If any other water sample which contain 120 PPm of MgSO_(4) , hardness in terms of CaCO_(3) is equal to =100 PPm. One litre of a sample of hard water (d=1 g/mL) cotains 136 mg of CaSO_(4) and 190 mg of MgCl_(2) . What is the total hardness of water in terms of CaCO_(3) ?

A sample of hard water contains 1 mg CaCl_2 and 1 mg MgCl_2 per litre. Calculate the hardness of water in terms of CaCO_3 present in per 10^(6) parts of water. (a). 2.5 ppm (b). 1.95 ppm (c). 2.15 ppm (d). 195 ppm

Solution of 100 ml water contains 0.73 g of Mg(HCO_(3))_(2) and 0.81g of Ca(HCO_(3))_(2) calculate the hardness ini terms of ppm of CaCO_(3)

10 L of hard water requires 0.28 g of line (CaO) for removing hardness. Calculate the temporary hardness in ppm of CaCO_(3) .

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