x=a cos theta,y=b sin theta

Eliminate theta from the following equation : x=h+a cos theta,y=k+b sin theta

Equation x =1 cos theta, y =b sin theta (a gt b) represent a conic sectin whose eccentricity e is given by

if theta is a parameter then x=a ( sin theta + cos theta), y=b( sin theta - cos theta ) respresents

if theta is a parameter then x=a ( sin theta + cos theta), y=b( sin theta - cos theta ) respresents

If x=a cos theta + b sin theta and y=a sin theta - b cos theta. then a ^(2) +b^(2) is equal to

If x=a cos theta + b sin theta and y=a sin theta - b cos theta. then a ^(2) +b^(2) is equal to

If x=a cos theta-b sin theta and y=a sin theta+b cos theta then prove that :x^(2)+y^(2)=a^(2)+b^(2)

The locus of the point x=a+b cos theta y=b+a sin theta is

Eliminate theta between the equation : x= h+a cos theta, y=k+ b sin theta .

If the line joining the points (a cos theta , b sin theta) and (a cos phi, b sin phi) .Prove that the equation of this lines is x/a "cos" (theta + phi)/2 + y/b"sin" (theta + phi)/2 = "cos" (theta -phi)/2