Which of the following increasing order of oxidising power is correct for the following species?
`VO_(2)^(+),MnO_(4)^(-),Cr_(2)O_(7)^(2-)`

Explanation

This is attributed to the increasing stability of the lower species to which they are reduced.
`MnO_(4^(-))` is reduced to `Mn^(2+)` which has stable half filled valence shell electron configuration `[3d^(5)]`.
`Cr_(2)O_(7^(2-))` is reduced to `Cr^(3+)` which has filled `t_(2g)^(3)` energy level of `3d` orbitals in octahedral crystal field spliting
`VO_(2^(+))` is reduced to `V^(3+)` which has electronic configuration `[Ar]^(18)3d^(2)4s^(0)`.
So the order of increasing stability of the reduced species is `Mn^(2+) gt Cr^(3+) gt V^(3+)` and, therefore, the increasing order of oxidising power is `VO_(2^(+)) lt Cr_(2)O_(7^(2-)) lt MnO_(4^(-))`.
Therefore, (A) option is correct.