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Aqurated copper (I) catin undergoes disp...

Aqurated copper (I) catin undergoes disproportionation as
`2Cu^(+)(aq) rarr Cu^(2+) (aq) + Cu`, because

A

`Cu^(+)` has `d^(10)` configuration

B

`Cu^(2+)` has `d^(10)` configuration

C

hydration energy of `Cu^(2+)` is higher than that of `Cu^(+)` which compensates second ionisation energy of Cu.

D

size of `Cu^(+) lt Cu^(2+)`

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The correct Answer is:
C
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Assertion: Aquated copper(I) cation undergoes disproportionation as: 2Cu^(+)(aq) to Cu^(2+)(aq)+Cu Reason: Hydration energy of Cu^(2+) is higher than that of Cu^(+) which compensates second ionisation energy of Cu.

The reaction Co(s) + Cu^(2+)(aq) rarr Co^(2+)(aq) + Cu(s) is-

Calculate equilibrium constant for tha disproportionation reaction : 2Cu^(2+)(aq)rarrCu(s)+Cu^(2+)(aq)" at " 25^(@)C ("Given " E_((Cu^(+)//Cu))^(@)=0.52 V, E_((Cu^(2+)//Cu^(+)))^(@)=0.16 V) .

The unique behaviour of CU, having a positive E^(@) (reduction potential) accounts for its inability to liberate H_(2) from acids,. Only oxidising acids (nitric acid and hot concentrated sulphuric acid) react with Cu. The high energy of transform Cu(s) to Cu^(2+)(aq.) is not balanced by its hydration enthalpy. On the other hand, All Cu(II) halides are known except iodide. in this case, Cu^(2+) oxidises I^(-) to I_(2) : 2Cu^(2+)+4I^(-) to 2CuI(s)+I_(2) However, copper (I) compounds are unstable in aqueous solution annd undergo disproportionation. 2Cu^(+)(aq.)toCu^(2+)(aq.)+Cu The stability of Cu^(2+)(aq.) rather than Cu^(+)(aq) is due to the much more negative Delta_(Hyd) of Cu^(2+)(aq.) than Cu^(+)(aq.) Q. Select the correct chemical change:

The unique behaviour of CU, having a positive E^(@) (reduction potential) accounts for its inability to liberate H_(2) from acids,. Only oxidising acids (nitric acid and hot concentrated sulphuric acid) react with Cu. The high energy of transform Cu(s) to Cu^(2+)(aq.) is not balanced by its hydration enthalpy. On the other hand, All Cu(II) halides are known except iodide. in this case, Cu^(2+) oxidises I^(-) to I_(2) : 2Cu^(2+)+4I^(-) to 2CuI(s)+I_(2) However, copper (I) compounds are unstable in aqueous solution annd undergo disproportionation. 2Cu^(+)(aq.)toCu^(2+)(aq.)+Cu The stability of Cu^(2+)(aq.) rather than Cu^(+)(aq) is due to the much more negative Delta_(Hyd) of Cu^(2+)(aq.) than Cu^(+)(aq.) Q. Consider the following transformation: CuSO_(4)(aq.)+KI(excess)to product Select the correct statement:

Statement-1: Many copper (I) compound are unstable in aqueous solution and undergo disproportionation. Statement-2: Cu^(2+) I mre stable than Cu^(+) because of much more negative Delta_(hyd)H^(@) of Cu^(2+) than Cu^(+) , which more than compensates for seconds ionisation enthalpy.

Calculate the standard free enegry change for the reaction: Zn + Cu^(2+)(aq) rarr Cu+Zn^(2+) (aq), E^(Theta) = 1.20V

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