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S(1) : Mn^(2+) compounds more stable tha...

`S_(1) : Mn^(2+)` compounds more stable than `Fe^(2+)` towards oxidation to their `+3` state.
`S_(2)` : Titanium and copper both in the first series of transition metals exhibits `+1` oxidation state most frequently.
`S_(3) : Cu^(+)` ions is stable in aqueous solutions.
`S_(4)` : The `E^(0)` value for the `Mn^(3+)//Mn^(2+)` couple much more positive than that for `Cr^(3+)//Cr^(2+)` or `Fe^(3+)//Fe^(2+)`,

A

`T TFT`

B

`TFFT`

C

`TFT T`

D

`FFTF`

Text Solution

Verified by Experts

The correct Answer is:
B

`S_(1)` : It is because `Mn^(2+)` has `3d^(5)` configuration which has extra stability.
`S_(2)` : Not Titanium but Copper, because with `+1` oxidation state an extra stable configuration `3d^(10)` results.
`S_(3)` : Not stable as it undergoes disproportionation `2cu^(+) (aq) rarr Cu^(2+)(aq) + Cu(s)`. The `E^(0)` value for this is favourable.
`S_(4)` : Much larger third ionisation energy of Mn (where the required change id `d^(5)` to `d^(4)`) is mainly responsible for this. This also explains why the `+3` state of Mn is of little importance.
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