In the elctrolysis of alumina using cryotile, the reaction that takes place at cathode is

Options

A. `12F^(-) to 6 F_(2)+12e^(-)`
B. `4H_(2)O+4e^(-) to 2H_(2)+4OH^(-)`
C. `6F_(2)+2Al_(2)O_(3) to 4AlF_(3)+3O_(2)`
D. `4Al^(3+)+12e^(-) to 4Al`

Answer

D