When ethylalcohol reacts with `Br_(2)` in presencce of red phosphorus the compound formed is

Options

A. `C_(2)H_(6)`
B. `PBr_(3)`
C. `CH_(3)Br`
D. `C_(2)H_(5)Br`

Answer

To solve the question regarding the reaction of ethyl alcohol with Br₂ in the presence of red phosphorus, follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant is ethyl alcohol, which has the chemical formula C₂H₅OH (or CH₃CH₂OH).

2. **Understand the Reaction Conditions**:
- The reaction takes place in the presence of Br₂ (bromine) and red phosphorus. Red phosphorus acts as a reducing agent and helps in the reaction.

3. **Reaction Mechanism**:
- When Br₂ is introduced, it dissociates into two bromine atoms (Br·).
- The hydroxyl group (–OH) in ethyl alcohol is replaced by a bromine atom (Br) through a substitution reaction.

4. **Formation of the Product**:
- The bromine atom attacks the carbon atom that was previously bonded to the hydroxyl group.
- The bond between the carbon and the oxygen in the hydroxyl group breaks, and the bromine atom attaches to the carbon atom.
- The resulting product is C₂H₅Br (or CH₃CH₂Br), which is bromoethane.

5. **Final Product**:
- The final compound formed is C₂H₅Br.

### Conclusion:
The compound formed when ethyl alcohol reacts with Br₂ in the presence of red phosphorus is **C₂H₅Br** (bromoethane).