The major product obtained when tert- butyl bromide is heated with sodium ethoxide is

Options

A. 2-Methy1-1-propene
B. Ehene
C. tert- Buty1methy1ether
D. Diethyl ether

Answer

To determine the major product obtained when tert-butyl bromide is heated with sodium ethoxide, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are tert-butyl bromide (C4H9Br) and sodium ethoxide (C2H5ONa).

### Step 2: Understand the Structure of Tert-Butyl Bromide
Tert-butyl bromide has the following structure:
- It is a tertiary alkyl halide, which means it has a carbon atom bonded to three other carbon atoms and one bromine atom. The structure can be represented as:

```
CH3
|
CH3-C-CH2-Br
|
CH3
```

### Step 3: Analyze the Reaction Type
When a tertiary alkyl halide reacts with an alkoxide, two possible pathways can occur: substitution (SN2 or SN1) or elimination (E2). However, due to the steric hindrance around the tertiary carbon, elimination is favored over substitution.

### Step 4: Determine the Major Product
Since tert-butyl bromide is a tertiary halide, the reaction with sodium ethoxide will lead to the formation of an alkene via an elimination reaction (E2 mechanism). The major product will be the most stable alkene formed from the elimination of HBr.

The elimination will occur as follows:
- The bromine atom will leave, and a hydrogen atom will be removed from one of the adjacent carbon atoms, resulting in the formation of a double bond.

### Step 5: Identify the Alkene Product
The major product formed from this reaction is 2-methylpropene (also known as isobutylene). The structure of 2-methylpropene can be represented as:

```
CH3
|
CH2=C-CH3
|
CH3
```

### Conclusion
The major product obtained when tert-butyl bromide is heated with sodium ethoxide is **2-methylpropene**.