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Pure homozygous offpriings in a silhbrid...

Pure homozygous offpriings in a silhbrid cross in the `F_(2) ` generation will be

A

`1//2`

B

`1//4`

C

`1//8`

D

`1//16`

Text Solution

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The correct Answer is:
To solve the question regarding the number of pure homozygous offspring in a dihybrid cross in the F2 generation, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Dihybrid Cross**: A dihybrid cross involves two traits, each represented by two alleles. For example, consider two traits: seed shape (round R and wrinkled r) and seed color (yellow Y and green y). 2. **Determine the Genotypes of Parents**: Assume both parents are heterozygous for both traits (RrYy). The parental genotypes would be RrYy x RrYy. 3. **Create a Punnett Square**: A dihybrid cross results in a 16-cell Punnett square. Each cell represents a possible genotype of the offspring. The combinations will include all possible combinations of the alleles from both parents. 4. **Count the Total Offspring**: In the F2 generation, there will be 16 different combinations of alleles (genotypes) from the Punnett square. 5. **Identify Homozygous Offspring**: Homozygous offspring are those with identical alleles for both traits. In our example, the homozygous combinations would be: - RRYY (homozygous round yellow) - RRYy (homozygous round yellow, but heterozygous for color) - RrYY (heterozygous for shape, but homozygous yellow) - rryy (homozygous wrinkled green) - rryY (homozygous wrinkled green, but heterozygous for color) - rrYY (homozygous for shape, but heterozygous for color) - Rryy (heterozygous for shape, but homozygous green) - RryY (heterozygous for both traits) - RrYy (heterozygous for both traits) The only pure homozygous combinations are RRYY and rryy. Thus, there are 2 homozygous combinations. 6. **Calculate the Ratio**: Out of 16 total combinations, only 2 are pure homozygous. Therefore, the ratio of pure homozygous offspring is: \[ \text{Ratio of homozygous} = \frac{2}{16} = \frac{1}{8} \] 7. **Conclusion**: The answer to the question is that the proportion of pure homozygous offspring in the F2 generation of a dihybrid cross is \( \frac{1}{8} \).

To solve the question regarding the number of pure homozygous offspring in a dihybrid cross in the F2 generation, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Dihybrid Cross**: A dihybrid cross involves two traits, each represented by two alleles. For example, consider two traits: seed shape (round R and wrinkled r) and seed color (yellow Y and green y). 2. **Determine the Genotypes of Parents**: ...
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Knowledge Check

  • The F_(2) -generation of a cross

    A
    Has a phenotypic ratio of 3 : 1
    B
    Is the result of the self-fertilisation or crossing of `F_(1)` individuals
    C
    Can be used to determine the genotype of individuals with the dominant phenotype
    D
    Has a phenotypic ratio that equals its genotypic ratio
  • When AABB and aabb are crossed, in F_(2) generations the ratio will be

    A
    `1//16`
    B
    `2//16`
    C
    `8//16`
    D
    `4//16`
  • In a monohybrid cross between two heterozygous individuals, percentage of pure homozygous individuals obtained in F_(1) generation will be

    A
    `25 %`
    B
    `50 %`
    C
    `75 %`
    D
    `100 %`
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