The unit of thermal conductivity is :

Options

A. ` Js^(-1) K`
B. `Js^(-1) m^(2)k`
C. `Jm^(-1)K`
D. `Js^(-1) m^(-1) K^(-1)`

Answer

D

Explanation

`Q= (KA(theta_(1)-theta_(2)t)/l) `
`therefore` `K= (Q xx l)/(A(theta_(1) - theta_(2))t`
Unit of K = (Jm)/(m^(2)K-s)` = `J/(s-mK)`