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Consider a compound slab consisting of t...

Consider a compound slab consisting of two different material having equal thickness and thermal conductivities `K` and `2K` respectively. The equivalent thermal conductivity of the slab is

A

2/3K

B

`sqrt 2`K

C

3K

D

(4/3)K

Text Solution

Verified by Experts

The correct Answer is:
D
`K_(eq) = (2K_(1)K_(2)) /(K_(1)+K_(2))= (2(K) (2K))/(K+2K) = 4/3 K`
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DC PANDEY-CALORIMETRY AND HEAT TRANSFER-Check points 16.3
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