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The maximum energy in thermal radiation ...

The maximum energy in thermal radiation from a source occurs at the wavelength 4000Å. The effective temperature of the source

A

7000 K

B

80000 K

C

`10^(4)` K

D

`10^(6)` K

Text Solution

Verified by Experts

The correct Answer is:
A
Applying Wein's law, we have, `lambda_(m)=b/T`
`T=b/(lambda_(m))= (2.89 xx 10^(-3))/(4000 xx 100^(-10))`
= 7225 K `~~ 7000K`
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