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In the figure, the distribution of energ...

In the figure, the distribution of energy density of the radiation emitted by a black body at a given temperature is shown. The possible temperature of the black body is

A

1500 K

B

2000 K

C

2500 K

D

3000 K

Text Solution

Verified by Experts

The correct Answer is:
B
`lambda_(m)T`=b, where b = `2.890 xx 10^(-3)`mK
`rArr T=b/lambda_(m)` = (2.89 xx 10^(-3))/(1.5 xx 10^(-6))` = 2000K
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