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The thickness of a metallic plate is 0.4...

The thickness of a metallic plate is 0.4 cm. The temperature between its two surfaces is `20^(@)C`. The quantity of heat flowing per second is 50 calories from `5cm^(2)` area. In CGS system, the coefficient of thermal conductivity will be

A

0.4

B

0.6

C

0.2

D

0.5

Text Solution

Verified by Experts

The correct Answer is:
C
Heat flowing per second, `Q/t=(KA(DeltaT))/t rArr 50 = (5 xx20K)/0.4rArrK = 1/5=0.2`
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