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The power radiated by a black body is P,...

The power radiated by a black body is P, and it radiates maximum energy around the wavelength `lambda_(0)`. If the temperature of the black body is now changed so that it radiates maximum energy around a wavelength `3lambda_(0)//4`, the power radiated by it will increase by a factor of

A

`256/81 P`

B

`27/64 P`

C

`64/27 P`

D

81/256 P`

Text Solution

Verified by Experts

The correct Answer is:
A

According to Wien,s law,
`lambda_(m)T` = constant
or `T alpha 1/(lambda_(m))`
`lambda_(m)` has become `3/4` times.
`therefore` Temperature will have become `4/3` times.
Now, according to Stefan's law, power `PalphaT^(4)`.
Therefore new power will be
`(4/3)^(4)P= 256/81P`
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