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Two identical conducting rods are first connected independently to two vessels, one containing water at `100^@C` and the other containing ice at `0^@C`. In the second case, the rods are joined end to end and connected to the same vessels. Let `q_1 and q_2` gram per second be the rate of melting of ice in the two cases respectively. The ratio `q_1/q_2` is
(a) `1/2` (b)`2/1` (c)`4/1` (d)`1/4`

A

`1/2`

B

`2/1`

C

`4/1`

D

`1/4`

Text Solution

Verified by Experts

The correct Answer is:
C

Initially the rods are in parallel
`Q/t = (theta_(1)-theta_(2))/R`
`rArr (Q/t)_(1) = (mL)/t = q_(1)L = (100-0)/(R/2)`............(i)
Finally when rods are in series
`rArr (Q/t)_(2) = (mL)/t = q_(2)L = (100-0)/(2R)`..............(ii)
From Eqs. (i) and (ii),
`q_(1)/q_(2) = 4/1`
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