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The thickness of a metallic plate is 0.4...

The thickness of a metallic plate is 0.4 cm. The temperature between its two surfaces is `20^(@)C`. The quantity of heat flowing per second is 50 calories from `5cm^(2)` area. In CGS system, the coefficient of thermal conductivity will be

A

0.2

B

0.3

C

0.4

D

0.5

Text Solution

Verified by Experts

The correct Answer is:
A

We know that
`Q/t=(KA(Deltatheta))/t`
`50 = (5 xx 20K)/(0.4)` or `K=(50 xx 0.4)/(5 xx 20) = 0.2`
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