An electron is accelerated in between two plates maintained at `1000 V`. What is the energy in eV acquired by the electrons? `(e=1.6 xx10^(-19) C)`

A charge of 2 C moves between two plates, maintained at a pd of 1 V . What is the energy acquired by the charge ?

An electron is accelerated under a potential difference of 64 V, the de-Brogile wavelength associated with electron is [e = -1.6 xx 10^(-19) C, m_(e) = 9.1 xx 10^(-31)kg, h = 6.623 xx 10^(-34) Js]

An electron (charge = 1.6 xx 10^(-19) coulomb) is accelerated through a potential of 1,00,000 volts. The energy required by the electron is

An electron is accelerated under a potential difference of 182 V. the maximum velocity of electron will be (Given, charge of an electron is 1.6xx10^(-19)C ms^(-1) and its mass is 9.1xx10^(-31)kg )

The Velocity of electrons accelerated bt potential difference of 1xx10^(4) V (the charge of the electron is 1.6xx10^(-19) C and mass is 9.11xx10^(-31) kg) is

An electron is projected with an initial velocity of 10^(7)ms^(-1) into an electric field between two parallel plates 1 cm apart. The electron enters the field at a point midway between the plates. If the electron just misses the positivity charged plate as it emerges from the field, find the magnnitude of the electric density between the plates. (Length of each plate is 2 cm, mass of electron= 9xx10^(-31) kg and charge of electron =1.6xx10^(-19) C)

Two insulting plates are both uniformly charged in such a way that the potential difference between them is V_2-V_1=20V . (i.e., plate 2 is at a higher potential). The plates are separated by d=0.1m and can be treated as infinity large. An electron is released from rest on the inner surface of plate 1. What is its speed when it hits plate 2? ( e=1.6xx10^-19C , m_e=9.11xx10^-31kg )